Read e-book online Trading for Tigers: High Probability Trading Tactics for PDF

By Walter T. Downs

ISBN-10: 0966945905

ISBN-13: 9780966945904

Provides a couple of per month, weekly and some day-by-day chart setups. those are primarily simply breakouts in keeping with bar styles with the occasional indicator for affirmation. moreover, there are backtested effects for every of them which are eye boggling if precise (75-90% win, three to at least one minimum). I figured there is substantial curve becoming and lots of hours of desktop scanning to discover ecocnomic styles. this is not inevitably undesirable, and given as those styles are all rather lengthy term.. few humans would really care to belly the stops essential to exchange it. attention-grabbing, still .. and back if those backtests are even seventy five% exact, you're looking at a few impressive setups.

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Extra info for Trading for Tigers: High Probability Trading Tactics for Stocks, Futures & Options

Sample text

La probabilità dell’evento Mk è data semplicemente da P(Mk ) = 1 1 1 1 ∑ P({nk}) = ∑ ζ (s) ns ks = ks . 51) n∈N Osserviamo che M p ∩ Mq = M pq se p e q non hanno divisori comuni. Con un facile argomento induttivo segue che se p1 , . . , p ∈ P sono numeri primi distinti si ha M p1 ∩ M p1 ∩ . . 51) P(M p1 ∩ M p1 ∩ . . ∩ M p ) = 1 = P(M p1 ) · P(M p1 ) · · · P(M p ) . 3 Probabilità condizionale e indipendenza 47 Dato che questa formula vale per ogni scelta di ∈ N e di p1 , . . , p ∈ P, abbiamo mostrato che gli eventi (Mp ) p∈P sono indipendenti.

44 11 1 = , 24 8 11 1 = . P({β v}) = P(Ac ∩ Rc ) = P(Ac ) P(Rc |Ac ) = P(Ac )(1 − P(R|Ac )) = 22 4 P({α v}) = P(A ∩ Rc ) = P(A) P(Rc |A) = P(A)(1 − P(R|A)) = In questo modo abbiamo calcolato la densità p(ω ) := P({ω }) per ogni ω ∈ Ω . 3 (o per verifica diretta) sappiamo che ciò determina completamente la probabilità P su (Ω , P(Ω )), per cui possiamo calcolare la probabilità di qualunque evento. 37) la risposta cercata. Nell’esempio precedente, scrivere esplicitamente lo spazio campionario Ω e determinare completamente la probabilità P è stato un esercizio istruttivo.

Come spazio campionario si può scegliere l’insieme di quattro elementi Ω = {α r, α v, β r, β v}, dove la prima lettera di ogni elemento ω ∈ Ω indica l’urna scelta e la seconda il colore della pallina estratta. L’evento A = {α r, α v} corrisponde a “l’urna scelta è α ”, l’evento R = {α r, β r} corrisponde a “la pallina estratta è rossa”. Dev’essere senz’altro P(A) = 1/2, visto che le urne vengono scelte con uguale probabilità. Inoltre, supponendo di aver scelto l’urna a, la probabilità di estrarre una pallina rossa è 3/4, perciò porremo P(R|A) = 3/4.

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Trading for Tigers: High Probability Trading Tactics for Stocks, Futures & Options by Walter T. Downs

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