By Nielsen W. M.

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**Extra info for Magnetic Analysis of Negative Ions in Mercury Vapor**

**Sample text**

59 that ^dvpxx = 0, fdvpxy = Vr, \dvpxz = Vq, so that the operator and accordingly i J p v A A dx dy (45). Hence I = y$dvp [r rV, H] [[mV] H] . mH, for div H= Now 0, as the H is due to an external field. the force according to Maxwell's theory mV . H - V mH . is = - [m [VH]], by = 0, mV (2), . H and ELECTRON THEORY FOR STATIONARY MEDIA [VH] = rotH=0, for as 41 H due is to currents or magnetisation Hence the resultant force is mV . H away from the The couple acting on the group 63. the of section will be, omitting terms in Couples in a magneto- origin.

If C are the current, expressed as a vector, Let us consider a stationary medium in which there * s e l ectr i c density p in addition to, and apart from, any effect of the polarisation D', and also 60. Electro- magnetic ^stationary a conduction current C. medium. * The equations (41) will + Frot G' 4- C = Frot H ...... e. div ( E + D ') = p ; strictly magnetic matter, having merely electrons. Let us now introduce a new quantity Hj defined by then the equations become -(E + D')+ C=FrotH with div(E + D') = /3, div(H 1 + 1 G') = .........

R, H + rV . H]) Now medium since the magnetic no supposed to have no charge and is Thus the resultant becomes electric polarisation. rV, H]. 59 that ^dvpxx = 0, fdvpxy = Vr, \dvpxz = Vq, so that the operator and accordingly i J p v A A dx dy (45). Hence I = y$dvp [r rV, H] [[mV] H] . mH, for div H= Now 0, as the H is due to an external field. the force according to Maxwell's theory mV . H - V mH . is = - [m [VH]], by = 0, mV (2), . H and ELECTRON THEORY FOR STATIONARY MEDIA [VH] = rotH=0, for as 41 H due is to currents or magnetisation Hence the resultant force is mV .

### Magnetic Analysis of Negative Ions in Mercury Vapor by Nielsen W. M.

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